Solving Momentum Problems

Solving Momentum Problems-72
Thomas Sullivan, the director of training for Building Momentum, runs a monthly workshop for military members known as, Innovation Boot Camp.“The problem solving aspect has always been at the center of what we do,” clarified Sullivan.

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Right off the bat we notice that in case A the ball is bouncing directly back in the horizontal direction, whereas in case B it’s taking a ricochet off the wall. – How conservation of energy is used to determine the initial and final velocity: We know that energy is conserved, what does that mean?

If we remember, that means that the energy in equals the energy out. Because the mass stays the same, this implies that the initial velocity and final velocity of the ball in both cases are equal.

Here we have to use trig, and end up with a change in momentum of 2*m*v*cos(theta), which is less than the change in case A because the vertical component of the velocity involves no change in direction.

That’s how I would break down a conceptual momentum problem like this.

– Analyzing the change in momentum equation and how it’s used to determine the difference between A and B: If we remember, the change in momentum would be the final momentum minus the initial momentum.

Starting with case A, you actually only have velocity and momentum in the horizontal direction.And in this video I go through an example of a conceptual change in momentum problem from a Physics 1 exam, step-by-step.A ball of mass = 10g slides on a frictionless table and strikes a barrier in two different cases as shown in the figure.“It is not too difficult to become a good problem solver, but a Ph. engineer will not know the difficulties of being an infantryman,” he explained further.Marines attending had to put their knowledge to the test during their culminating event.For further information, including about cookie settings, please read our Cookie Policy .By continuing to use this site, you consent to the use of cookies.In A, it bounces right back to retrace its path; in B, it bounces diagonally (path shown in dotted line).The initial speed of the ball is the same in both cases and no energy is lost in either collision. (A) There is not enough information to determine which case has a greater change in momentum (B) The change in the ball’s momentum is zero for both cases (C) The change in the ball’s momentum is greater for case A than for B (D) The change in the ball’s momentum is the same in both cases (but not zero) (E) The change in the ball’s momentum is greater for case B than for A – Breaking down the problem statement and final answer: It says the correct answer is C, the change in the ball’s momentum is greater for case A than for case B.“The goal for me is to learn, gather materials, and bring it back to teach my Marines,” Terrazas Jr. “If they understand and can do these kinds of tasks, than that can continuously get passed on.” Marines interested in attending upcoming workshops may contact [email protected] information.We use cookies to make interactions with our website easy and meaningful, to better understand the use of our services, and to tailor advertising.


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